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(B) The angular width of the central maximum in a single-slit diffraction pattern is given by $	heta = \frac{2\lambda}{a}$,where $\lambda$ is the wav

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(B) The angular width of the central maximum in a single-slit diffraction pattern is given by $	heta = \frac{2\lambda}{a}$,where $\lambda$ is the wavelength of light and $a$ is the slit width.From this relation,we see that $	heta \propto \lambda$.Since the wavelength of blue light $(\lambda_{B})$ is smaller than the wavelength of yellow light $(\lambda_{y})$,i.e.,$\lambda_{B} Therefore,the angular width of the diffraction pattern for blue light will be smaller than that for yellow light,meaning the fringes will become narrower.

How will the diffraction pattern change when yellow light is replaced by blue light? The fringe will be :-

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